Physics, asked by abhinashgupta24701, 1 year ago

If the man pushes with a force of 1005N, the box will slide up the ramp at a rate of 1.1m/s². How much normal force is acting on the box?

Answers

Answered by sohanq8

0

Normal force will be mg

Mg = (F/a)g = (1005/1.1)10 = 9136.4N

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