Math, asked by sunitasingh8984, 5 hours ago

if the manufacturer gains 10% the wholesale dealer gains 15% it and the retail dealer gains 25% then what is the cost of production of a water geyser the retail price of which is is ₹1265

pls explain it step by step its urgent​

Answers

Answered by ayujain111
0

Answer:

Answer:- Rs.800

Step-by-step explanation:

Let us consider the cost of production of table as Rs. ‘x’.

It is said that the manufacturer gains 10

.

The wholesale dealer gains 15

and the retailer gains 25

.

The retail price will be taken as 100% of Rs.1265

.

Then the manufacturer gains 10

. Thus the manufacturer sells it for (100+10)

of the manufacturing price =110

of Rs. x.

Similarly the wholesale dealer gains 15

.Thus the wholesale dealer sells it at (100+15)

of the price he paid to the manufacturer =115

of 110

of Rs. x.

The retailer gains 25%. Thus the retailer sells it at (100+25)

of the price he paid to the wholesale dealer =125

of 115

of 110

of Rs. x.

We have been given the retail price of the table as Rs.1265

.

Hence by the problem, we need to find the value of x.

125

of 115

of 110

of x=Rs.1265

By solving the above expression, we get the cost of production of a table.

110100×115100×125100×x=1265.

Rearranging and cross multiplying the above expression we get,

x=1265×100×100×100110×115×125.

Solve the above expression and get the value of x.

x=Rs.800

Hence we got the cost of production of a table as Rs.800.

Similar questions