Question

If the mass defect in a nuclear fusion process is 0.3% then the energy released in the fusion of 1kg of material will be

Answer 1

Hii dear,

# Answer- E = 7.5×10^7 kWh

# Explaination-

Here mass defect is calculated by,

Δm=0.3%×1=3×10^-3

Energy released in nuclear fussion reaction is given by,

E = Δm.c^2

E = 3×10^-3 × (3×10^8)^2

E = 2.7×10^14 J

In kWh, energy is

E = 2.7×10^14/(3.6×10^6)

E = 7.5×10^7 kWh

Energy liberated is 7.5×10^7 kWh.

Hope this helps you.

Answer 2

Answer:

Explanation:

The mass defect in a particular nuclear reaction = 0.3 gms (Given)

Thus, mass defect will be -  

Δm = 0.3%×1

= 3×10`³

The energy released in nuclear fusion reaction is given by - E = Δmc²  

Thus, according to the formula -  

E = Δm.c²  

E =0.3/1000 × (3 × 10`8)²

= 2.7 × 10`13J    

= 2.7 × 10`13/ 3.6 × 10⁶

= 7.5 × 10⁶

Therefore,  the amount of energy liberated in kilowatt hours is 7.5 × 10⁶ Kwh.