Question

If the mass of a body is double then by what percent its Kinetic energy will increased or decreased

Answer 1

Your answer is :

Let initial kinetic energy is

1/2 mv^2

when mass become double

then kinetic energy is

1/2×2mv^2 = mv^2

% change in kinetic energy is

mv^2/1/2mv^2 × 100

= 2×100 = 200%

change in kinetic energy is 200%

Answer 2

HEY MATE HERE IS YOUR ANSWER

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We know that,

$= > k.e = \frac{1}{2} m {v}^{2}$

When mass is doubled it becomes

$= > \frac{1}{2} 2m {v}^{2} = m {v}^{2}$

PERCENTAGE change in Kinetic Energy is :-

$= > \frac{m {v}^{2} }{ \frac{1}{2} 2m {v}^{2} } = m {v}^{2}$

➡️ 2 × 100

➡️ 200 %

Therefore,

PERCENTAGE increased by 200 %.










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