Physics, asked by prasaddurga43105, 6 months ago

If the mass of a body is reduced to half and its velocity is doubled
calculate me perantage increase in ke?
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Answers

Answered by sudhirgupta001
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Explanation:

Let the Mass of the body be = m

Velocity of the body = v

initial \: kinetic \: energy =  \frac{1}{2}m {v}^{2}

ATQ,

Mass of the body = m/2

Velocity of Body = 2v

new\: kinetic \: energy =  \frac{1}{2} (\frac{m}{2}) {(2v)}^{2}

 =  \frac{1}{2}( \frac{m}{2})(4 {v}^{2}) = 2( \frac{1}{2}m {v}^{2})

new \: kinetic \: energy = 2(initial \: kinectic \: energy)

Increase %

 \frac{new \: ke - initial \: ke}{initial \: ke} \times 100

 \frac{2 (\frac{1}{2}m {v}^{2}) -  1(\frac{1}{2}m {v}^{2})}{ \frac{1}{2}m {v}^{2}  }  \times 100

 \frac{ \frac{1}{2}m {v}^{2}}{ \frac{1}{2}m {v}^{2}  }  \times 100 = 100\%

Therefore , the percentage increase in KE is 100 %

I hope it helps you. If you have any doubts, then don't hesitate to ask.

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