If the mass of a car is 1000 kg, then the amount of work to be done to increase its velocity from 30 ms–1 to 40 ms–1 is
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Work done is equal to change in kinetic energy as per work energy theorem.
Here je1 and ke2 are kinetic energy at initial and final conditions respectively.
So ke2=1/2×1000×40^2=800000 joule.
similarly,ke1=1/2×1000×30^2=450000joule.
So work done=
800000-450000=350000 joule or 3.5×10^5 joule.
Thanks.
Tripathy
Here je1 and ke2 are kinetic energy at initial and final conditions respectively.
So ke2=1/2×1000×40^2=800000 joule.
similarly,ke1=1/2×1000×30^2=450000joule.
So work done=
800000-450000=350000 joule or 3.5×10^5 joule.
Thanks.
Tripathy
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