If the mass of a car is 3 quintals and it is running at a speed of 100km/h and it increases its speed to 120km/h then find the work done by car engine.
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Answer:
5.09 x 10^5J
Explanation:
We know that change in kinetic energy = work done
mass of car = 3 quintals = 3000kg
1m²/s² = 5²/18² kmph²
kinetic energy = 1/2 mv²
let v1 = 100kmph
v2 = 120 kmph
change in kinetic energy = 1/2 mv² -1/2mv²
work done = 1/2 x m {v1 +v2}{v1 - v2}
= 1/2 x 3000 x 20 x 220
= 3000 x 2200kgkmph²
= 3000 x 2200 x 25 / 324
work done = 5.09 x 10^5J
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