Question

if the mass of a planet is 8 times the mass of the earth and its radius is twice then the radius of the earth what will be the escape velocity for the planet

Answer 1

Mp = Me ×8
Mp = 6×10²⁴ ×8
Mp = 48×10²⁴kg

Rp = Re × 2
Rp =6.4×10^6 ×2
Rp =12.8×10^6 m

Vesc of planet = √2Gm/R
= √2 × 6.67 ×10^-11 Nm/kg² × 48×10²⁴ kg
× 12.8×10^6m
= √8,196.096 × 10^19
= 8,196.096 × 10^17
= 8,196.096 × 10¹⁴km/s