Science, asked by gunjalrohitkisan2003, 1 year ago

if the mass of a planet is eight times the mass of the earth and its radius is twice the radius of earth, what will be the escape velocity for the planet?

Answers

Answered by amulyar
4

Given in the question :-

Planet mass is 8 times that earth

Planet radius is twice then the radius of earth.

Let mass of the Earth = M

Radius of the Earth = R


Now, we know that The equation to get escape velocity  


v = √(2 g r)



 If the mass of planet is eight times then escape velocity = 2 √2 times. 


Escape velocity reduced to by 1/√2. If radius expands twice

Hence the net escape velocity will be increase.


2 √2 ×  (1/√2)= 2 times now.

Now it is clear that the escape velocity of that planet will be 2 times from the earth.


Escape velocity of the earth = 11.2 km/s

Escape velocity of that planet = 2 × 11.2 = 22.4 km/sec.




Hence the escape velocity of that planet will be 22.4 km/s


Hope it Helps :-)





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