If the mass of an object is 50 kg and its velocity changes from 50 m/s to 90 m/s, then find the work done by the object?
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From work energy theorem
Work done = change in KE
Work done = 1/2mv^2 - 1/2mu^2
v=90m/s
u=50m/s
W = 1/2m (90^2 - 50^2)
W = 1/2*50(40*140)
W= 140 kJ
Work done = change in KE
Work done = 1/2mv^2 - 1/2mu^2
v=90m/s
u=50m/s
W = 1/2m (90^2 - 50^2)
W = 1/2*50(40*140)
W= 140 kJ
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