Question

if the mass of body is 30 kg and its speed is 5mls then find total acceleration yo the body after 3s and force applied on it.​

Answer 1

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PHYSICS

A constant force acting on a body of mass 3.0kg changes its speed from  2.0m s−1 to 3.5m s−1 in 25s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

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ANSWER

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

a=t(v−u)

   =25(3.5−2)=0.06m/s2

As per Newton's second law of motion, force is given as:

F=ma

    =3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

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Answer 2

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