Chemistry, asked by shwethsenthilkumar, 7 months ago

If the mass of neutron is doubled and mass of electron is halved then find the percent by which it is increased.
(a) 20%
(b)30%
(c)40%
(d)50%

Answers

Answered by perinanajwala85
1

Answer:

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Answered by harsh3764
4

Answer:

6C¹²→e=6

Number of protons = 6=6amu

Number of neutrons = 6=6amu

Total mass = (6+6)=12amu

Mass of the electron is negligible.

If the mass of the neutron is doubled, then the total mass = (6×2)+6= 18amu

Therefore, the % of the increase = =

18−12/12×100=50%

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