If the mass of neutron is doubled and mass of electron is halved then find the percent by which it is increased.
(a) 20%
(b)30%
(c)40%
(d)50%
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Answer:
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Answered by
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Answer:
6C¹²→e=6
Number of protons = 6=6amu
Number of neutrons = 6=6amu
Total mass = (6+6)=12amu
Mass of the electron is negligible.
If the mass of the neutron is doubled, then the total mass = (6×2)+6= 18amu
Therefore, the % of the increase = =
18−12/12×100=50%
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