Question

If the mass of neutron is doubled and that of proton is halved...then find the molecular mass of h2o

Answer 1

Expert

14 C 6

number of proton= 6

number of neutron = 8 

mass of proton = 6 amu

mass of neutron = 8 amu

total mass = 6 + 8 = 14

now the mass of neutron s halved so,= 8/2 = 4

the mass of proton is doubles = 6 x2

new mass = 6x2 + 4 = 16 amu

% of increase in mass= 16 -14/ 14 x 100

= 14.28 %

I hope my answer is correct