Question

If the mass of SO2 used in the reaction 2SO2 +O2 →SO3 is 2g then the mass of SO3 ​Produced is?

Answer 1

Answer:

2.5g

Explanation:

First of all the correct equation for this reaction is    2SO2 + O2 ⇒ 2SO3

Mole ratio of each element used in the reaction          2         1           2

Relative molecular mass of SO2 is 64 and the mass of SO2 used in the reaction is 2g

Moles = Mass / Relative molecular mass

          = 2 / 64

          = 0.03125 mol

Using mole ratio we know that the moles of SO2 used in the reaction is the same as moles of SO3 produced in the reaction ( 2 : 2 = 1 : 1 )

So 0.03125 moles of SO3 are produced in the reaction

Relative molecular mass of SO3 is 80

Moles = Mass / Relative molecular mass (Same formula)

Since we need to find mass of SO3 produced in the reaction

Mass = Moles * Relative molecular mass

         = 0.03125 * 80

         = 2.5g

Answer 2

Answer:

2.5 gm

Explanation:

Balanced Equation : 2SO2 + O2 ----> 2SO3

2 mole of SO2 gives 2 mole of SO3

therefore, 1 mole of SO2 gives 1 mole of SO3

Calculate mole of SO2 : Given mass / Molar mass

                                        2 / 64 = 1 / 32 .

therefore, mole of SO3 = 1 / 32

Now calculate mass of 1 / 32 mole of SO3 :

                                                                      =  mole x molar mass

                                                                      = 1 / 32 x 80 gm.

                                                                      = 2.5 gm