Question

if the mass of the app of a planet is 8 times the mass of the earth and its radius is the price and the radius of the earth what will be the escape velocity for that planet

Answer 1

Hey mate!!! ❤❤Here's ur answer!! ❤❤
________________________________

$mass \: of \: planet \: M \: = 8 \times mass \: of \: earth \:$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 8 \times 6 \times {10}^{24}$

$radius \: of \: planet \: R= 2 \times radius \: of \: earth \:$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 6.4 \times {10}^{6}m$

$g = gravitational \: constant \: = 6.67 \times {10}^{ - 11}n \: {m}^{2} {kg}^{2}$

$so \: escape \: velocity \: = \sqrt{} \frac{2gm}{r }$

$escape \: velocity \: = \sqrt{( \frac{2 \times 6.67 \times {10}^{ - 11} \times 8 \times 6 \times {10}^{24} }{2 \times 6.64 \times {10}^{6} } })$

$\: \: \: \: \: \: \: = 22.4 km/sec$

_________________________________

Question:What is escape velocity?
Answer:Escape velocity of the planet is the velocity thrown at which the object escapes the gravitational potential of the planet.
________________________________

Hope this helps you!!! ^_^