Question

If the mass of the body is halved and velocity gets doubled then final kinetic energy would be .........of initial.(a) same(b) four times(c) double(d) eight times

Answer 1

Answer is here  case1 is the one which is before making changes

Answer 2

Explanation:

The kinetic energy of an object is given by :

$K=\dfrac{1}{2}mv^2$

Here

m is mass

v is velocity

If mass of the body is halved, m' =m/2 and velocity is doubled, v'=2v

New kinetic energy becomes,

$K'=\dfrac{1}{2}m'v'^2\\\\K'=\dfrac{1}{2}\times \dfrac{m}{2}\times (2v)^2\\\\K'=\dfrac{1}{2}\times \dfrac{m}{2}\times 4v^2\\\\K'=2mv^2\\\\K'=2\times K$

So, the new kinetic energy of the object gets doubled. Hence, the correct option is (c).

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