Question

if the mass of the coin 0.50 kg. what is its weight?​

Answer 1

Answer:

Let the recoil velocity of gun be V.

Mass of gun M

gun

=5.0 kg

Mass of bullet M

bullet

=0.01 kg

Velocity of bullet V

bullet

=250 m/s

Initial momentum of the system P

i

=0

Applying the conservation of linear momentum : P

f

=P

i

Or M

gun

V+M

bullet

V

bullet

=0

Or 5×V+0.01×250=0

⟹ V=−0.5 m/s

Answer 2

Answer:

5 N

Explanation:

Weight(mg) is acting downwards. And value of g≈10 m\s² and value of m=0.50kg.

Hence, mg=0.50kg×10m/(second square)=5N

I hope it will help you.