Question

if the mass of the earth is doubled and the distance of the Moon revolving around the earth is also doubled then find the new time period of revolution of moon take the present time of revolution is 28 days

Answer 1

Answer:

Explanation:

T = 28 days = 2419200 s

r = 4×$10^{5}$ km = 4×${10^8}$ m

G = 6.67×$10^{-11}$Nm²/kg

we know that

T = 2π√(r³/GM)

T² = 4π^2×r³/GM

M = 4π²×r³/GT²

M = 4×3.14² × (4×$10^8$)³/ (6.67×$10^{-11}$×2419200²)

M = 6.46×$10^{24}$ kg

Hence

mass of earth is 6.46×$10^{24}$ kg.