Question

If the mass of two objects are 10kg and 5 kg and the distance between them is 10 find the force of attraction between them.

Answer 1

Given

☞ Mass of one object = 10 kg

☞ Mass of 2nd object = 5 kg

☞ Distance b/w them = 10 m

To find

☞ Force of attraction b/w them.

Solution

From the data we have ;

☞ Mass of 1st object (m₁) = 10 kg

☞ Mass of 2nd object (m₂) = 5 kg

☞ Distance (d) = 10 m

Now we will use Newton's law :-

☛ F = (Gm₁m₂)/d²

Where,

• G is Gravitational constant
• G = 6.67 × 10-¹¹ m³ kg-¹ s-²

Now putting values we get,

⟼ F = (6.67 × 10-¹¹ × 10 × 5)/10²

⟼ F = (6.67 × 10-¹¹ × 50)/100

⟼ F = (6.67 × 10-¹¹)/2

⟼ F = 3.335 × 10-¹¹ N

But if you keep value of G as constant,

⟼ F = G(10 × 5)/10²

⟼ F = G(50)/100

⟼ F = G/2 N

∴ Force of attraction between them = 3.335 × 10-¹¹ N or, G/2 N.

Answer 2

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If the mass of two objects are 10kg and 5 kg and the distance between them is 10 find the force of attraction between them...

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✒Given : -

• Mass of 1st Object $\sf{({m}_{1})}$=10kg
• Mass of 2nd Object $\sf{({m}_{2})}$=5kg
• Total Distance = ?

✒To Find : -

• Force of attraction = ?

✒By Using Newton's Law : -

$\leadsto\sf{F=\dfrac{G({m}_{1})({m}_{2})}{{d}^{2}}}$

➴Here : -

• G = Gravitational Constant .
• G = 6.67 × 10-¹¹ m³ kg-¹ s-² ..

✒On Substituting Values : -

$\dashrightarrow\sf{F=\dfrac{(6.67\times{{10}^{-11}\times{10}\times{5})}}{{10}^{2}}}$

$\dashrightarrow\sf{F=\dfrac{(6.67\times{{10}^{-11}\times{\cancel{50})}}}{\cancel{100}}}$

$\dashrightarrow\sf{F=\dfrac{(6.67\times{{10}^{-11})}}{2}}$

$\dashrightarrow\sf{F=3.335\times{{10}^{-11}}}N$

✒Now ,

✒By keeping value of G as constant : -

$\dashrightarrow\sf{F=\dfrac{G(10\times{5)}}{{10}^{2}}}$

$\dashrightarrow\sf{F=\dfrac{G(50)}{100}}$

$\leadsto\sf{F=\dfrac{G}{2}}N$

✒Therefore , Force of attraction between then is G/2 N or 3.335 × 10-¹¹ ..