Question

If the mass of water in vessel "D" is 500 gm and area of its base is 0.7m2 , find the pressure exerted at the base of the vessel, in SI unit?

Answer 1

Answer:

2 N/m²

Explanation:

Mass of water, m = 500 g = 500÷1000 = 0.5 kg

Weight of water, F = mg = 0.5×9.8 N

Area of base of vessel = 0.7m²

Pressure = F/A = (0.5×9.8)÷0.7 = 0.5×4 = 2 N/m²