Question

if the mass ratio of N2 and co2 is 7 : 11 in a closed cylindrical then there molar ratio will be​

Answer 1

if the mass ratio of N2 and co2 is 7 : 11 in a closed cylindrical then there molar ratio will be

answer : molar ratio = 1 : 1

explanation : given, mass ratio of N2 and CO2 is 7 : 11 in a closed cylindrical vessel.

let proportionality constant is x,

then, mass of N2 gas = 7x

and mass of CO2 gas = 11x

we know,

• molecular mass of N2 = 28g/mol
• molecular mass of CO2 = 44g/mol

so, no of moles of N2 = 7x/28 = x/4

no of moles of CO2 = 11x/44 = x/4

hence, molar ratio of N2 and CO2 = (x/4)/(x/4) = 1/1

Answer 2

Explanation:

Because it's a closed cylinder, No gas can diffuse out.

Given, Mass ratio of N2 and CO2 is 7 : 11.

Let us say, m g of Nitrogen is taken.

then, 11 m/7 g of Carbon dioxide is taken.

Converting into moles,

1 mole of Nitrogen = 28 g

1 mole of Carbon dioxide = 44 g.

We have,

Number of moles of N2 = m/28

Number of moles of CO2 = 11m/7 ÷ 44

Molar ratio ( N2 : CO2)

$\frac{m}{28} \ratio \: \frac{11m}{7 \times 44} \\ \\ \frac{m}{28} \ratio \: \frac{m}{7 \times 4} \\ \\ \frac{m}{28} \ratio \: \frac{m}{28} \\ \\ 1 \ratio 1$

Therefore, Molar ratio of N2, CO2 is 1 : 1 when they are taken in the ratio of 7 : 11 of their masses.