Question

if the maximum height attained by a projectile is equal to the maximum horizontal range of another projectile then what will be the ratio of their velocity of projection​

Answer 1

Explanation:

let the 1st and 2nd projectile be projected at u and v velocities at an angle @ with the horizontal respectively.

so,

Hmax1=u²sin²@/2g

and

Rmax2=v²sin2@/g

given:

Hmax1=Rmax2

u²sin²@/2g=v²sin2@/g

u²/v²=4cot@

u/v=2√cot@