Physics, asked by harshita15161355, 8 months ago

If the maximum height is 20 root 3 and range is 80 m then find the
initial angle of projection and initial velocity.
Please explain with detailed answer.

Class 11- Physics
Chapter- Motion in a plane​

Answers

Answered by Anonymous
0

Given-

u=20m/s , θ=30

o

, t=0.5s

Initial velocity-

u

=ucosθ

i

^

+usinθ

j

^

u

=u(cos30

o

i

^

+sin30

o

j

^

)

u

=20(

2

3

i

^

+

2

1

j

^

)

u

=10

3

i

^

+10

j

^

acceleration a=−g

j

^

=−10

j

^

since acceleration is acting downward

v

=

u

+

a

t

v

=(10

3

i

^

+10

j

^

)−(10

j

^

×0.5)

v

=10

3

i

^

+5

j

^

Change in velocity=Δ

v

=

v

u

=−5

j

^

Magnitude of change in velocity =5m/s

A short method is-

Δ

v

=acceleration×t=10×0.5=5m/s

5 m/ s

Answered by armirji
1

Answer:

Explanation: SEE YOU MUST BE KNOWING THAT R/H=4/TAN THETA.

BY APPLYING THIS YOU WILL GET THAT TAN THETA=ROOT 3.

HENCE THETA =60 DEGREE.

NOW APPLY THE FORMULA FOR MAX HEIGHT YOU WILL GET THE ANSWER.

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