If the maximum height is 20 root 3 and range is 80 m then find the
initial angle of projection and initial velocity.
Please explain with detailed answer.
Class 11- Physics
Chapter- Motion in a plane
Answers
Answered by
0
Given-
u=20m/s , θ=30
o
, t=0.5s
Initial velocity-
u
=ucosθ
i
^
+usinθ
j
^
⟹
u
=u(cos30
o
i
^
+sin30
o
j
^
)
⟹
u
=20(
2
3
i
^
+
2
1
j
^
)
u
=10
3
i
^
+10
j
^
acceleration a=−g
j
^
=−10
j
^
since acceleration is acting downward
v
=
u
+
a
t
⟹
v
=(10
3
i
^
+10
j
^
)−(10
j
^
×0.5)
v
=10
3
i
^
+5
j
^
Change in velocity=Δ
v
=
v
−
u
=−5
j
^
Magnitude of change in velocity =5m/s
A short method is-
Δ
v
=acceleration×t=10×0.5=5m/s
5 m/ s
Answered by
1
Answer:
Explanation: SEE YOU MUST BE KNOWING THAT R/H=4/TAN THETA.
BY APPLYING THIS YOU WILL GET THAT TAN THETA=ROOT 3.
HENCE THETA =60 DEGREE.
NOW APPLY THE FORMULA FOR MAX HEIGHT YOU WILL GET THE ANSWER.
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