If the maximum kinetic energy of the photoelectrons is E when a radiation of frequency V is incident on a photosensitive metal, then the maximum kinetic energy of the photoelectrons when the frequency of the incident radiation is doubled is:
a)2E
b)E/2
c)E+hv
d)E-hv
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Answer:
From Einstein's equation for photoelectric effect , the maximum kinetic energy , K=hν−W
where ν= frequency of incident light , h= Planck's constant and W= work function of metal.
When ν is made double, K
′
=2hν−W=2(hν−W)+W=2K+W
Thus, kinetic energy of photoelectrons will be more than doubled when incident frequency is doubled
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