Question

If the maximum value of 3sin theta + cos theta = Root x then find x.

Answer 1

Answer:

10

Explanation:

3sin∅+cos∅

maximum value=$\sqrt{x}$

general form==>a sin∅+b cos∅

a=3,b=1.

$\sqrt{a^2+b^2} =\sqrt{x}$

a^2+b^2=x

3^2+1^2=x

∴x=10

Answer 2

Answer:

the value of x= 10

Explanation:

The maximum value of

the general form is

a sin ∅+ b cos ∅= √(a²+b²)

then

3 sin ∅+ cos ∅= √x

where

a= 3, b = 1

maximum value = √(3²+1²)

=√10

Therefore

x= 10