Question

if the me diagonals of a rhombus are 24dm and 10dm , then te perimeter of the rhombus will be

Answer 1

Answer:

Since Diagonals of rhombus bisect each other at right angles.

So AO = 24 /2 =12

and OD = 10/2 =5

Now,

using Pythagoras theorem in triangle AOD

AD^2 = AO^2+OD^2

= 12^2 + 5^2

=144+ 25

=169

So AD = 13 dm

PERIMETER = 13 × 4 = 52 dm