Question

if the mean of 16 number is 8.now ,2 is added to every number ,what will the new mean

Answer 1

Answer:

$\huge \fbox{answer}$

It will be 10, here’s why…

The mean is the average of the 16 numbers. (Where all 16 numbers will have been totalled and then divided by the number of numbers.)

So lets reverse it, we know the mean is 8 and there are 16 numbers so 8 * 16 = 128 (which is the total if you were adding up all 16 numbers).

If we are adding 2 to each of the 16 numbers, it is fair to assume that this would add 32 (2 x 16) to the total of adding up all the numbers.

128 + 32 = 160. Then the new mean is simply the new total divided by the number of numbers.

160 / 16 = 10

$\huge \fbox{(OR)}$

∴ Mean = (x+32)/16

⇒ 8+2 =10.

So, the required new mean is 10.

Answer 2

Answer:

It will be 10, here’s why…

The mean is the average of the 16 numbers. (Where all 16 numbers will have been totalled and then divided by the number of numbers.)

So lets reverse it, we know the mean is 8 and there are 16 numbers so 8 * 16 = 128 (which is the total if you were adding up all 16 numbers).

If we are adding 2 to each of the 16 numbers, it is fair to assume that this would add 32 (2 x 16) to the total of adding up all the numbers.

$\sf 128 + 32 = 160.$

Then the new mean is simply the new total divided by the number of numbers.

$\sf 160 / 16 = 10$

(OR)

$\sf Mean = (x+32)/16$

$\sf ⇒ 8+2 =10.$

So, the required new mean is 10.

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mark the above as brainliest please