If the mean of 4,7,x,y and 10 is 8, then find the value of x+y
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Answered by
0
Solution :
Given mean of 4,7,x,y and 10 is 8
Sum of the observations
= 4+7+x+y+10
= 21 + x + y -----( 1 )
Number of observations
= 5 ----( 2 )
Now ,
mean = 8 ( given )
=> (1)/(2) = 8
=>( 21+x+y)/5 = 8
=> 21+x+y = 40
=> x + y = 40 - 21 = 19
Therefore ,
x + y = 19
••••
Answered by
1
No. Of terms = 5
Mean = sum of all terms ÷ no.of terms
Mean=8
So, sum of all terms ÷ no.of terms = 8
4+7+x+y+10÷5 =8
21+x+y÷5=8
On cross multiply,
21+x+y=40
Therefore, x+y=40-21
x+y= 19
Thank you I hope that this answer helps you
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