Question

if the mean of 5,6,8,10,p and 12 is 20 find the value of p​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

Given :

Mean of 5,6,8,10,p and 12 is 20

To Find :

Value of p

Mean =$\sf\dfrac{Sum \: of \: all \: terms \: }{No \: of \: terms}$

$Mean = \dfrac{5 + 6 + 8 + 10 + p + 12}{6} = 20$

$\sf= > \dfrac{19 + 10 + p + 12}{6} = 20$

$\sf= > \dfrac{29 + p + 12}{6} = 20$

$\sf= > \dfrac{41 + p}{6} = 20$

$\sf= > 41 + p =1 20$

$\sf = > p = 120 - 41 = 79$

$\therefore$ Value of p is 79

Check:

$\sf= > \dfrac{5 + 6 + 8 + 10 + 79 + 12}{6}$

$\sf= > \dfrac{19 + 22 + 79}{6}$

$\sf= > \dfrac{120}{6} = 20$

Answer 2

Step-by-step explanation:

Value of p

Mean =\sf\dfrac{Sum \: of \: all \: terms \: }{No \: of \: terms}

Noofterms

Sumofallterms

Mean = \dfrac{5 + 6 + 8 + 10 + p + 12}{6} = 20Mean=

6

5+6+8+10+p+12

=20

\sf= > \dfrac{19 + 10 + p + 12}{6} = 20=>

6

19+10+p+12

=20

\sf= > \dfrac{29 + p + 12}{6} = 20=>

6

29+p+12

=20

\sf= > \dfrac{41 + p}{6} = 20=>

6

41+p

=20

\sf= > 41 + p =1 20=>41+p=120

\sf = > p = 120 - 41 = 79=>p=120−41=79

\therefore∴ Value of p is 79

plz follow me ✌️♥️