Question

If the mean of 5 consecutive odd integar is 13 find the sum of the largest and smallest integars

Answer 1

Answer:

Step-by-step explanation:

the odd numbers be n-2,n-4,n,n+2,n+4

mean=n-2+n-4+n+n+2+n+4/5=13

5n=13*5

n=13

the larget integer is n+4=13+4=17

smallest one=n-2=13-2=11

Answer 2

Answer:

26

Step-by-step explanation:

Mean of 5 consecutive odd integers = 13

Odd integers can be written as :

a , a + 2 , a + 4 .........

Eg : 1 , 3 , 5 .......

Mean = ( a + a + 2 + a + 4 + a + 6 + a + 8 ) / 5

= > 13 = ( 5 a + 2 + 4 + 6 + 8 ) / 5

= > 5 a + 20 = 13 × 5

= > 5 a + 20 = 65

= > 5 a = 65 - 20

= > 5 a = 45

= > a = 45/5 = 9

Numbers are :

9

9 + 2

9 + 4

9 + 6

9 + 8

...

9 , 11 , 13 , 15 , 17

Sum of largest smallest = 9 + 17

= 26