Math, asked by agbley284, 9 months ago

If the mean of 5 positive integer is 15, what the maximum possible difference between the largest and smallest of these 5 numbers.

Answers

Answered by amitnrw
0

Given :  mean of 5 positive integers is 15

To find : maximum possible difference between the largest and the smallest of these 5 numbers

Solution:

mean of 5 positive integers is 15,

Sum of 5 numbers  = 5 * 15  = 75

To have maximum possible Difference

one number should be be largest possible & all other should be Smallest

Smallest positive integer  =  1

number can be 1  , 1  , 1  , 1  71

maximum possible difference between the largest and the smallest = 71 - 1  = 70

if each number Has to be different

then possible numbers

1 , 2 , 3 , 4 , 65

maximum possible difference between the largest and the smallest = 65 - 1  = 64

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