Question

If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these 5 numbers

Answer 1

Step-by-step explanation:

If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these 5 numbers

• Let the 5 positive integers be p,q,r,s,t,. According to the question, this is equal to 15
• Then we get the equation as p + q + r + s + t / 5 = 15
• Or we get p + q + r + s + t = 75
• Assuming the four integers are equal to 1 we get p = q = r = s = 1 and so t = 71
• Now smallest possible number is 1 and the largest is 71.
• So the difference will be 71 – 1 = 70

Reference link will be

https://brainly.in/question/18205620