Math, asked by jovapash61, 10 months ago

if the mean of 5 positive integers is 15 , what is the maximum possible difference between the largest and the smallest of these 5 numbers?...I need help guys

Answers

Answered by Suketu
1

Answer:

20

Step-by-step explanation:

Assuming the five numbers as a,b,c,d,e

ie. (a+b+c+d+e)/ 5 = 15

=>> c = 15

(a+b+c+d+e) = 75

Assuming numbers as 5,10,15,20,25

Hence the difference is 25 - 5 = 20

Answered by rosey25
2

Answer:

The maximum possible difference between the largest and the smallest of these 5 numbers is 70. Condition 2 => If all 5 positive integers be different. We can see that there can't be any more numbers which we can take as 5 positive integers which will give us the maximum possible difference.

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