Question

If the mean of a,b,c,d is K, then what is the mean of a) a+b,2b,c+b, d+b

Answer 1

Answer:

mean of a, b, c, d=(a+b+c+d)/4=K

mean of a+b,2b,c+b,d+b

=(a+b+2b+c+b+d+b)/4

=(a+b+c+d+4b)/4

=(a+b+c+d)/4. + 4b/4

=K+b

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Answer 2

The mean of a+b, 2b, c+b, and d+b is k+b.

Given:

The mean of a,b,c, and d is K.

To Find:

We have to find the mean of a+b, 2b, c+b, and d+b.

Solution:

This is a simple problem for mean.

Let us tackle this problem.

We can easily solve this problem as follows,

According to the question,

the mean of a, b, c and d is k.

So,

$\frac{a+b+c+d}{4} =k$ ..................(i)

Now,

The mean of a+b, 2b, c+b, and d+b is

= $\frac{a+b+2b+c+b+d+b}{4}$

= $\frac{a+5b+c+d}{4}$

= $\frac{a+b+c+d}{4}+ b$

= $k+b$ ................(by equation (i))

Hence, the mean of a+b, 2b, c+b, and d+b is k+b.

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