if the mean of a set of observations x1,x2,x3......x10 is 25.find the mean of x1+3,x2+6,x3+9......x30+30 is
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Answer:
41.5
Step-by-step explanation:
Given
if the mean of a set of observations x1,x2,x3......x10 is 25.find the mean of x1+3,x2+6,x3+9......x30+30 is
Now n = 10 and mean = 25
So mean = x1 + x2 + x3 + ---------+xn / n
25 = x1 + x2 + x 3+-----------+ x 10 / 10
Now x1 + x2 +----------+ x 10 = 250
Also x1 + 3, x2 + 6 x3 + 9----------xn + 30
Now mean = x1 + 3 + x2 + 6+------+x10 + 30 / 10
Mean = (x1 + x2 +-----+ x10) + (3 + 6 + 9 +------30)
Mean = 250 + 165 / 10
= 415 / 10
Hence Mean = 41.5
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