Question

if the mean of a1 a2 a3 an IS A then A is equal to​

Answer 1

Answer:

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Answer 2

The value of A = [ a₁+ a₂ + a₃ + ...+ a$_{n}$ ]/n

Given:

The mean of a₁ a₂ a₃..... a$_{n}$ is A

To find:

The value of A

Solution:

Formula used:

Mean of a data = Sum of observations/ Number of observations

Here we have  

Given data a₁, a₂, a₃ .... a$_{n}$    

Sum of observations = a₁+ a₂ + a₃ + ...+ a$_{n}$

Number of observations = n

As we know

Mean = Sum of observations/ Number of observations

Mean of  a₁, a₂, a₃ .... a$_{n}$ = [ a₁+ a₂ + a₃ + ...+ a$_{n}$ ]/n

Given that the mean of a₁ a₂ a₃..... a$_{n}$ is A  

=> A = [ a₁+ a₂ + a₃ + ...+ a$_{n}$ ]/n  

Therefore,

The value of A = [ a₁+ a₂ + a₃ + ...+ a$_{n}$ ]/n

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