If the mean of frequency distribution is 8.1 and Σfixi = 132 + 5k, Σfi = 20, then k =
(a)3
(b)4
(c)5
(d)6
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SOLUTION :
The correct option is (d) : 6
Given : MEAN of the frequency distribution = 8.1 , Σfixi = 132 + 5k , Σfi = 20
MEAN = Σfixi /Σfi
8.1 = (132 + 5k) / (20)
20 × 8.1 = 132 + 5k
162 = 132 + 5k
5k = 162 - 132
5k = 30
k = 30/5 = 6
k = 6
Hence, the value of k is 6 .
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So correct option is (D)
So correct option is (D)
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