Question

If the mean of n observations
afi, af2, af3,..., afn is aF then
(a) aF = afi + af2 + afz + ... + afn
(b) a(fi +F)+a(f2+F)+... +a(fn +F)=0
(c) a(fi-aF) +(af 2 - aF)+... +a(fn-aF)=0
(d) sigma(afi - aF) = a
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Answer 1

Answer:

Step-by-step explanation:

If the mean of n observations

afi, af2, af3,..., afn is aF then  

(a) aF = afi + af2 + afz + ... + afn

(b) a(fi +F)+a(f2+F)+... +a(fn +F)=0

(c) a(fi-aF) +(af 2 - aF)+... +a(fn-aF)=0

(d) sigma(afi - aF) = a

aF = (afi + af2 +  af3+  ,..., + afn)/n

=> naF = afi + af2 +  af3+  ,..., + afn

=> aF + aF + aF + .........n times  = afi + af2 +  af3+  ,..., + afn

=> 0 = (afi -aF)+ (af2 -aF)+  (af3 - aF) +  ,..., + (afn-aF)

=> (afi -aF)+ (af2 -aF)+  (af3 - aF) +  ,..., + (afn-aF) = 0

=> a(fi - F) + a(f2 -F) + a(f3 - F) +............ + a(fn - F) = 0

none of the given options is correct