Math, asked by sanjay702594, 7 months ago

If the mean of the following data is 59, find the missing frequency.

Class 10-30 30-50 50-70 70-90 90-110

Frequency 10 7 5 X 12​

Answers

Answered by hukam0685
1

Step-by-step explanation:

Given:Mean of the following data is 59.

\begin{array}{|c|c|}</p><p>\cline{1-2} Class&amp; Frequency\\</p><p>\cline{1-2} 10-30&amp; 10\\</p><p>\cline{1-2} 30-50&amp; 7\\</p><p>\cline{1-2} 50-70&amp; 5\\</p><p>\cline{1-2} 70-90&amp; X\\</p><p>\cline{1-2} 90-110&amp; 12\\\cline{1-2}</p><p>\end{array}

To find: X

Solution:

We know that

Mean =  \frac{ \Sigma \: x_if_i}{ \Sigma \: f_i}  \\

Find class mark for each class and put the values in the formula,in order to find X

\begin{array}{|c|c|c|c|}</p><p>\cline{1-4} Class&amp; Frequency&amp; x_i&amp;x_if_i\\</p><p>\cline{1-4} 10-30&amp; 10&amp;20&amp;200\\</p><p>\cline{1-4} 30-50&amp; 7&amp; 40&amp;280\\</p><p>\cline{1-4} 50-70&amp; 5&amp; 60&amp;300\\</p><p>\cline{1-4} 70-90&amp; X&amp; 80&amp;80X\\</p><p>\cline{1-4} 90-110&amp; 12&amp; 100&amp;1200\\</p><p>\cline{1-4}Total&amp;34+X&amp;&amp;1980+80X\\\cline{1-4}</p><p>\end{array}

Put the values

59 =  \frac{1980 + 80X}{34 + X} \\  \\ cross \: multiply \\  \\ 59(34 + X) = 1980 + 80X\\  \\ 59 \times 34 + 59X = 1980 + 80X \\  \\ 59X - 80X = 1980 -2006  \\  \\  - 21X = -26 \\  \\ 21X =26  \\  \\ X =1.24  \\  \\

Thus,

Value of missing frequency is 1.24

Which is not possible.

Frequency should be positive integer.

*Note: Some data is incorrect in this question.To show the method question is solve here.

It is advisable to upload correct data.

Hope it helps you.

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Answered by charisma47
0

Answer:

X=1.24 is your answer.....

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