Question

if the mean of the following distribution is 10 then find the value of p ​

Answer 1

$\begin{array}{|c|c|c|}\cline{1-3}x_i&f_i&f_ix_i\\\cline{1-3}2&3&6\\4&4&16\\6&2&12\\8&1&8\\10&2&20\\12&p&12p\\\cline{1-3}&12+p&12p+62\\\cline{1-3}\end{array}$

$\text{From the table,}$

$\Sigma{f_i}=12+p$

$\Sigma{f_ix_i}=12p+62$

$\text{Now,}$

$\text{Mean=}\displaystyle\frac{\Sigma{f_ix_i}}{\Sigma{f_i}}$

$\implies\,10=\displaystyle\frac{12p+62}{12+p}$

$\implies\,120+10p=12p+62$

$\implies\,2p=58$

$\implies\boxed{\bf\,p=29}$

$\therefore\textbf{The value of p is 29}$

Find more:

If the mean of 17, 19, 24, 15, 18, 16, x, 14 is 17. ſind the value of x​

https://brainly.in/question/14104575#

Answer 2

Answer:

p= 29...............................

its correct