IF THE MEAN OF THE FOLLOWING DISTRIBUTION IS 2.6 , then find the value of k. variables (Xi) are 1,2,3,4,5 resoectively and frequency (Fi) are 4,5,k,1 and 2 respectively
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Answered by
141
Given
X=1,2,3,4,5
F=4,5,k,1,2
Mean =2.6
Mean =€fx/€f
2.6=(1x4+2x5+3xk+4x1+5x2)/4+5+k+1+2
2.6=(4+10+4+10+3k)/12+k
2.6=(28+3k)/12+k
2.6(12+k)=(28+3k)
31.2+2.6k=28+3k
31.2-28=3k-2.6k
3.2=0.4k
K=3.2/0.4
K=8
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X=1,2,3,4,5
F=4,5,k,1,2
Mean =2.6
Mean =€fx/€f
2.6=(1x4+2x5+3xk+4x1+5x2)/4+5+k+1+2
2.6=(4+10+4+10+3k)/12+k
2.6=(28+3k)/12+k
2.6(12+k)=(28+3k)
31.2+2.6k=28+3k
31.2-28=3k-2.6k
3.2=0.4k
K=3.2/0.4
K=8
This is ur ans hope it will help you in case of any doubt comment below
tnwramit1:
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Answered by
5
Given:
Mean=2.6
To find:
The value of k
Solution:
The value of k is 8.
The given mean can be obtained by dividing the sum of the variables and their frequency's product by the sum of their frequencies.
So, mean=∑xi×fi/∑fi
The value of ∑xi×fi is as follows-
=1×4+2×5+3×k+4×1+5×2
=4+10+3k+4+10
=28+3k
∑fi=4+5+k+1+2=12+k
Mean=2.6
2.6=(28+3k)/(12+k)
2.6(12+k)=28+3k
31.2+2.6k=28+3k
3.2=0.4k
8=k
Therefore, the value of k is 8.
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