if the mean of the series exceeds the mean by 3 find,by what number the mode exceeds its mean
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Answer:
Mode exceeds the mean by 9.
Step-by-step explanation:
3(median) = 2(mean) + mode
Let the mean be 'x'
So, median will be x + 3
Then, according to the question
3(x+3) = 2(x) + mode
3x + 9 = 2x + mode
3x - 2x + 9 - mode
x+9 = mode
Now, mode - mean
⇒ x+9 - x
= 9
So, mode exceeds the mean by 9.
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