If the mean of x and 1/x is M then mean of x³ and 1/x³ is
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Given mean x and
x1 is M∴M= 2x+x1
⇒x+ x1
=2M
Cube both the sides
∴(x+ x1 )3
=(2M) 3
⇒x 3 + x 31
+3(x+ x1 )=8M 3
⇒x 3 + x 31
=8M 3 −3(x+ x1 )
⇒x 3 + x 31
=8M 3 −3(2M)
⇒x 3 + x 3 1
=2M(4M 2 −3)
Then mean of x 3 and x 3 1
So 2x 3 + x 3 1
=2M(4M 2 −3)
⇒x 3 + x 3 1
=M(4M 2 −3)
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