Math, asked by krishtrikha, 3 months ago

If the mean of x, x+3,x+6,x+9,x+12,x+15.is 18 find the mean of first four observation​

Answers

Answered by Anonymous
10

Given :

  • Given observations = x,(x + 3),(x + 6),(x + 9),(x + 12),(x + 15).

  • Mean of all the observations = 18.

  • No. if term = 6

To find :

Mean of first four observations.

Solution :

We know the formula for mean,i.e,

\boxed{\bf{Mean = \dfrac{\Sigma x_{i}}{n}}}

Where :

  • \bf{\Sigma x_{i}} = Sum of all observations.

  • \bf{n} = No. of all observations.

By using the formula for mean and substituting the values in it, we get :

:\implies \bf{Mean = \dfrac{\Sigma x_{i}}{n}} \\ \\ \\

:\implies \bf{Mean = \dfrac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5} + x_{6}}{n}} \\ \\ \\

:\implies \bf{18 = \dfrac{x + (x + 3) + (x + 6) + (x + 9) + (x + 12) + (x + 15)}{6}} \\ \\ \\

:\implies \bf{18 = \dfrac{(x + x + x + x + x + x) + (3 + 6 + 9 + 12 + 15)}{6}} \\ \\ \\

:\implies \bf{18 = \dfrac{6x + 45}{6}} \\ \\ \\

:\implies \bf{18 \times 6 = 6x + 45} \\ \\ \\

:\implies \bf{108 = 6x + 45} \\ \\ \\

:\implies \bf{108 - 45 = 6x} \\ \\ \\

:\implies \bf{63 = 6x} \\ \\ \\

:\implies \bf{\dfrac{63}{6} = x} \\ \\ \\

:\implies \bf{10.5 = x} \\ \\ \\

\boxed{\therefore \bf{x = 10.5}} \\ \\ \\

Hence the value of x 10.5.

From the above equation , we get :

  • First term = x = 10.5

  • Second term = (x + 3) = 13.5

  • Third term = (x + 6) = 16.5

  • Fourth term = (x + 9) = 19.5

  • Fifth term = (x + 12) = 22.5

  • Sixth term = (x + 15) = 25.5

Now to find the mean of first four terms of the observation.

\boxed{\bf{Mean = \dfrac{\Sigma x_{i}}{n}}}

Where :

  • \bf{\Sigma x_{i}} = Sum of all observations.

  • \bf{n} = No. of all observations.

By using the formula for mean and substituting the values in it, we get :

:\implies \bf{Mean = \dfrac{\Sigma x_{i}}{n}} \\ \\ \\

:\implies \bf{Mean = \dfrac{x_{1} + x_{2} + x_{3} + x_{4}}{n}} \\ \\ \\

:\implies \bf{Mean = \dfrac{10.5 + 13.5 + 16.5 + 19.5}{4}} \\ \\ \\

:\implies \bf{Mean = \dfrac{10.5 + 13.5 + 16.5 + 19.5}{4}} \\ \\ \\

:\implies \bf{Mean = \dfrac{60}{4}} \\ \\ \\

:\implies \bf{Mean = 15} \\ \\ \\

\boxed{\therefore \bf{Mean = 15}} \\ \\ \\

Hence the mean of first four terms of the observation is 15.

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