Question

if the meanof a frequency distribution is 8.1 and fixi =132+5k, f =20 find k

Answer 1

use formula,
$\overline{x}=\frac{f_ix_i}{f}$
where $\overline{x}$ is the mean , f is number of data values .

here given,
$\overline{x}=8.1$
$f_ix_i=132+5k$
and $f=20$

so, 8.1 = (132 + 5k)/20

8.1 × 20 = 132 + 5k

162 = 132 + 5k

162 - 132 = 5k

30 = 5k

k = 6

hence, k = 6

Answer 2

please Mark this has brainlist answer