Math, asked by ar540619, 1 month ago

if the measure of a diagonal of a square is
$10\sqrt{2}$
Find the measure of its side

Answers

Answered by nikhitaN

1

Answer:

10

Step-by-step explanation:

diagonal/√2=side

pythagoras theorem:

√a^2+b^2=diag^2

for square a=b

√2a^2=diag^2

√2*a=diag

a=diag/√2

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