Question

if the measure of a diagonal of a square is
$10\sqrt{2}$
Find the measure of its side​

Answer 1

Answer:

10

Step-by-step explanation:

diagonal/√2=side

pythagoras theorem:

√a^2+b^2=diag^2

for square a=b

√2a^2=diag^2

√2*a=diag

a=diag/√2