if the measure of an angle is 60degree and the perimeter of a rhombus is 48cm, then find the area of the rhombus
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Answer:
cm²
Step-by-step explanation:
Let ABCD be a RHOMBUS.
Let ∠ABC be 60°
Given, perimeter of rhombus is 48 cm.
We know that all the 4 sides of a rhombus are equal.
∴ Side of the rhombus = 48÷4
= 12 cm
∠ABC = 60° ; We know that in ΔABC, AB=BC [∵ They are sides of a rhombus]
∴ ∠BAC = ∠BCA = (180°-60°)÷2
= 60°
∴ ∠BAC = ∠BCA = 60°
∴ We come to know that ΔABC is an EQUILATERAL TRIANGLE.
⇒ Area of ΔABC =
⇒ Area =
⇒ Area = cm²
⇒ ∴ Area of rhombus ABCD = 2×Area of ΔABC
= 2×
= cm²
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