Math, asked by anutreasa950, 10 months ago

if the measure of each base angle of an isosceles triangle is 7 times the measure of the vertex angle find the angles​

Answers

Answered by Anonymous
7

7x + 7x + x = 180 ( angle sum property )

15x = 180

x = 180/15

x = 12

angles are 84 , 84 , 12

Answered by SteffiPaul
2

Given,

  • The measure of each base angle of an isosceles triangle is 7 times the measure of the vertex angle.

To find,

  • We have to find the angles.

Solution,

We can simply find the angles by using the angle sum property of a triangle.

       Let the measure of the vertex angle be 'x'

then, the measure of the base angle is 7x.

As we know that in an isosceles triangle, two sides are equal so the angles opposite to equal sides are also equal.

Then, the angles of the base are 7x, 7x and that of the vertex is x.

Using the angle sum property, we have

      7x + 7x +x = 180°    (Angle Sum Property)

                 15x = 180°

                    x  = 180/15

                    x = 12

The angles are 7(12) = 84°, 84°, and 12°.

Hence, if the measure of each base angle of an isosceles triangle is 7 times the measure of the vertex angle, then the angles are 84°, 84°, and 12°.

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