If the measure of one angle of a triangle is 80 and the other two angles are equal in measure then find the measure of each equal angle of the triangle.
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3
Answer:
Sum of All angles of a triangle are supplementary= 180°
80+x+x=180°
80+2x=180
2x=180-80=100
x=100/2=50°
hence each angle is
50°
50°
80°
Answered by
1
Step-by-step explanation:
Sum of the angles of a triangle = 180°
One angle = 80°
Remaining two angles are equal
let the the angles be= x and x
x+x+80° = 180°
2x+ 80°= 180°
2x= 180°- 80°
2x = 100°
x= 100÷ 2
x = 50°
one equal angle = 50°
another equal angle = 50°
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