if the measure of one side of right triangular field is 42cm.If the difference of the lengths of hypotenuse and the other is 14cm . Find the side of the triangle and its area .
Answers
Answered by
12
Answer:
Given one side of the triangle as 42 m
Let the other side be x and hypotenuse be h
Hence h x = 14
⇒ h = x + 14
By Pythagoras theorem we know that square of hypotenuse is equal to sum of the squares of the other two sides.
⇒ (x + 14)2 = x2 + (42)2
⇒ x2 + 28x + 196 x2 1764 = 0
⇒ 28x 1568 = 0
⇒ 28x = 1568
∴ x = 56
h = x + 14 = 56 + 14 = 70 m
Area of triangle = (1/2) × 56 × 42
= 1176 sq m
Step-by-step explanation:
Similar questions